MATH SOLVE

3 months ago

Q:
# Subtract 11b^2-4b+711b 2 β4b+711, b, start superscript, 2, end superscript, minus, 4, b, plus, 7 from b^2+8b-9b 2 +8bβ9b, start superscript, 2, end superscript, plus, 8, b, minus, 9.

Accepted Solution

A:

Answer:-730b^2-1404b-16Step-by-step explanation:11b^2-4b+711b2-4b+711b^2-4b+7=(11+711)b^2+(-4+711.2-4-4)b+7= 722b^2+1410b+7 =Ab^2+8b-9b2+8b-9b^2+8b-9=(1-9)b^2+(8-9.2+8+8)b-9= -8b^2+6b-9 =BB-A= (-8-722)b^2+(6-1410)b+(-9-7)= -730b^2-1404b-16